Replying to a comment on:

Why you don't fall through the floor (Sonnet) by ?-Dave_Mysterious-?

Schrödinger’s equation: -(ħ²/2M)grad²φ(x,y,z) + Vφ(x,y,z) = Eφ( z,y,z) For a particle in a box: V = 0 if 0 < x,y,x < a = ∞ otherwise Try a solution of the form φ = Nsin(2πlx/a)sin(2πmy/a)sin(2πnz/a) Where N is the normalisation factor. φ must go to zero at x,y,z = a, therefore l,m,n are integers. So, E = -(1/2M)(2πħ/a)²(l² + m² + n²) Now, pressure P = ∂E/∂V And dV = d³a = d(a³) = 3a²da Therefore P = (1/3a²)∂E/∂a This is quantum pressure.

Everyone 9-Dec-03/9:43 AM
Dear oh dear, Dave. Honestly. You can't haul yourself out of the sewers with a feeble attempt at 'zaniness'. I'm afraid you owe the entire poemeranking community an apology for thinking that neither rectangular nor triangular manhole covers could fall down the manholes they cover. You should have said a torus shaped manhole cover couldn't fall down a manhole - at least that provides an example of a non-circular solution to the manhole cover crisis. -10-




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