Replying to a comment on:

Why you don't fall through the floor (Sonnet) by ?-Dave_Mysterious-?

Schrödinger’s equation: -(ħ²/2M)grad²φ(x,y,z) + Vφ(x,y,z) = Eφ( z,y,z) For a particle in a box: V = 0 if 0 < x,y,x < a = ∞ otherwise Try a solution of the form φ = Nsin(2πlx/a)sin(2πmy/a)sin(2πnz/a) Where N is the normalisation factor. φ must go to zero at x,y,z = a, therefore l,m,n are integers. So, E = -(1/2M)(2πħ/a)²(l² + m² + n²) Now, pressure P = ∂E/∂V And dV = d³a = d(a³) = 3a²da Therefore P = (1/3a²)∂E/∂a This is quantum pressure.

ARTIE 10-Dec-03/8:32 AM
Sorry Dave, I have already offered the job to Everyone, but now, I am going to throw in the Medical bennies. "Tri-again" was merely a play on words - not a clue, which is still what you're missing. Nice try on the equalateral triangle but you still lack the third dimension. I won't ask whether you're familiar with the concept of "Six degrees of Freedom" - you're still stuck behind the first two. No Tupperware in the house? You could have made a trip to the store.
45° and 0°...??? What more am I to conclude from you here? Remember this: Gravity is our friend, always has been, always will be. If you drop a golf ball straight into a hole, what is the angle of approach? This is the second question on the test. (Your scholarship is at stake.)




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